25x^2=54

Solution for 25x^2=54 equation:

25x^2=54

We move all terms to the left:

25x^2-(54)=0

a = 25; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·25·(-54)
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{6}}{2*25}=\frac{0-30\sqrt{6}}{50}
=-\frac{30\sqrt{6}}{50}
=-\frac{3\sqrt{6}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{6}}{2*25}=\frac{0+30\sqrt{6}}{50}
=\frac{30\sqrt{6}}{50}
=\frac{3\sqrt{6}}{5}
$